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3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. For each node a color from {1, 2, 3} certifier: Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. Check if for each edge (u, v ), the color.

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For each node a color from {1, 2, 3} certifier: Given a graph g(v;e), return 1 if and only if there is a proper colouring of. 3color = { g ∣ g. Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. Check if for each edge (u, v ), the color.

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Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. For each node a color from {1, 2, 3} certifier: 3color = { g ∣ g. Check if for each edge (u, v ), the color. Given a graph g(v;e), return 1 if and only if there is a proper colouring of.

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3color = { g ∣ g. Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. For each node a color from {1, 2, 3} certifier: Check if for each edge (u, v ), the color. Given a graph g(v;e), return 1 if and only if there is a proper colouring of.

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Check if for each edge (u, v ), the color. Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. For each node a color from {1, 2, 3} certifier: 3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of.

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Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. 3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. For each node a color from {1, 2, 3} certifier: Check if for each edge (u, v ), the color.

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Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. For each node a color from {1, 2, 3} certifier: Check if for each edge (u, v ), the color. 3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of.

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3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. Check if for each edge (u, v ), the color. Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. For each node a color from {1, 2, 3} certifier:

Prove that 3Coloring is NP Hard (starting with SAT as known NP hard

3color = { g ∣ g. Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. Check if for each edge (u, v ), the color. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. For each node a color from {1, 2, 3} certifier:

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For each node a color from {1, 2, 3} certifier: Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. 3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. Check if for each edge (u, v ), the color.

For each node a color from {1, 2, 3} certifier: Given a graph $g = (v, e)$, is it possible to color the vertices using just 3. 3color = { g ∣ g. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. Check if for each edge (u, v ), the color.

For Each Node A Color From {1, 2, 3} Certifier:

3color = { g ∣ g. Check if for each edge (u, v ), the color. Given a graph g(v;e), return 1 if and only if there is a proper colouring of. Given a graph $g = (v, e)$, is it possible to color the vertices using just 3.